If a^2 b^2 c^2-ab-bc-ca = 0 then prove that a=b=c

If a²+b²+c²-ab-bc-ca=0,prove that0:02:20

If a²+b²+c²-ab-bc-ca=0,prove that a=b=c | Algebraic Identity | Algebraic Formula | Proof | (a-b)²

Algebraic Identities |0:08:04

Algebraic Identities | If a^2+b^2+c^2-ab-bc-ca = 0 then prove that a=b=c | algebra | class 9 maths

If a²+b²+c²-ab-bc-ca=0, find0:02:25

If a²+b²+c²-ab-bc-ca=0, find a:b:c | Algebraic Identity |Algebraic Formula | Algebraic Proof |(a-b)²

If a2 + b2 + c2 –0:07:17

If a2 + b2 + c2 – ab – bc – ca = 0 then prove that a = b = c | Class 9 Maths Polynomials | NCERT

Maths Tricks |0:00:49

Maths Tricks | If a+b+c=0 then (a^2+b^2+c^2)/(ab+bc+ca)=? #shorts , ShortCut Tricks #ssc

(a+b+c)²=a²+b²+c²+2(ab+bc+ca) Proof ||0:01:25

(a+b+c)²=a²+b²+c²+2(ab+bc+ca) Proof || a plus b plus c Whole Square Identity Proof

if a2+b2+c2-ab-bc-ca=0 then0:04:39

if a2+b2+c2-ab-bc-ca=0 then prove that a=b, b=c, c=a | if a2+b2+c2-ab-bc-ca=0 then prove that a=b=c

Resolve into linear0:01:46

Resolve into linear factors `a^2+b^2+c^2-ab-bc-ca`

Mock Paper 21:46:33

Mock Paper 2 Discussion (Part-1) | JEE Main 2025 | Mathemagix JEE

Mathematics Solution 'a+b+c=15,0:01:14

Mathematics Solution 'a+b+c=15, a²+b²+c²=83, ab+bc+ca=?'

`a+b+c=0,t h e0:01:22

`a+b+c=0,t h e n(a^2)/(b c)+(b^2)/(a c)+(c^2)/(a b)=`

IX Grade :0:05:19

IX Grade : Algebra - If ab+bc+ca =1 and a+b+c =2 then (a+b)^2 + (b+c)^2 + (c+a)^2 = ?

Montrer que pour0:02:21

Montrer que pour tout réel a, b et c: a²+b²+c²≥ab+bc+ca

If `a^2(b+c), b^2(c+a),c^2(a+b)`0:02:43

If `a^2(b+c), b^2(c+a),c^2(a+b)` are in A.P., then prove that a,b,c are in A.P. or `ab+bc+ca=0`

If a^2+b^2+c^2=20 and0:02:28

If a^2+b^2+c^2=20 and a+b+c=0 find ab+bc+ca

#(a+b+c)² #algebraicidentity If0:01:18

#(a+b+c)² #algebraicidentity If a+b+c=10,ab+bc+ca=31,find a² +b² +c² | (a+b +c)²| Mathematics Class9

If a+b+c=0 find0:08:01

If a+b+c=0 find the value ab/a²+ab+b² +bc/b²+bc+c² +ca/c²+ca+a²

If a+b+c=0 find0:03:09

If a+b+c=0 find value of (a+b)^2 /(ab) + (b+c)^2 /(bc) + (c+a)^2 /(ca) #ALGEBRA

If a+b+c=0, then0:07:02

If a+b+c=0, then prove that a^2/(2a^2+bc) + b^2/(2b^2+ac) + c^2/(2c^2+ab) =1.

An Algebra Problem0:04:11

An Algebra Problem | a+b+c = 2 , ab+bc+ca = 1 , (a+b)^2 + (b+c)^2 + (c+a)^2 = ?

if a +0:00:40

if a + b + c = 6 and (a² + b² + c² )= 14 then (a b + BC + CA) =

#a+b+c=? If a²+b²+c²=45,ab+bc+ca0:01:20

#a+b+c=? If a²+b²+c²=45,ab+bc+ca =38;find a+b+c | (a+b+c)² |Algebraic Identity |Mathematics Class 9

If `a +0:02:03

If `a + b + c = 0`, then the value of `(a+b)^2/(ab)+(b+c)^2/(bc)+(c+a)^2/(ca)`is

If a+b+c=0, then0:03:26

If a+b+c=0, then value of a2/bc + b2/ca + c2/ab is. (abc≠0)